pat1001-A+B Format

前言：自己平时不玩ACM，保研需要，也做做题目，练练手，C语言也学得不好，C++就直接没学过。浙大复试通知上也是说只能用C或者C++。所以……

下面是pat1001，题目如下：

Calculate a + b and output the sum in standard format — that is, the digits must be separated into groups of three by commas (unless there are less than four digits).

Input

Each input file contains one test case. Each case contains a pair of integers a and b where -1000000 <= a, b <= 1000000. The numbers are separated by a space.

 

Output

For each test case, you should output the sum of a and b in one line. The sum must be written in the standard format.

Sample Input

-1000000 9

Sample Output

-999,991

helloworld类型的，答案如下：

#include <stdio.h>
void myprint(int);
int main()
{
	int a , b ;
	int sum;
	scanf("%d%d",&a,&b);
	sum = a + b;
	myprint(sum);
	return 0;
}
void myprint(int num)
{
/*	if(abs(num) > 999999999){
		printf("%d",(num/1000000000));
		printf(",");
		printf("%d%d%d",num/100000000%10,num/10000000%10,num/1000000%10);
		printf(",");
		printf("%d%d%d",num/100000%10,num/10000%10,num/1000%10);
		printf(",");
		printf("%d%d%d",num/100%10,num/10%10,num%10);
	}else
*/	if(num < 0 ) {
		printf("-");
		num = - num;
	}
	if((num) > 999999){
		printf("%d",(num/1000000));
		printf(",");
		printf("%d%d%d",num/100000%10,num/10000%10,num/1000%10);
		printf(",");
		printf("%d%d%d",num/100%10,num/10%10,num%10);
	}else if((num) > 999)
	{
		printf("%d",(num/1000));
		printf(",");
		printf("%d%d%d",num/100%10,num/10%10,num%10);
	}else{
		printf("%d",num);
	}
}

。

结果，通过……